So, greater amount of energy(heat) has to be provided to the liquid to make it boil. But what about the molecules of the liquid which are above the surface of the liquid, that have been converted into gaseous phase? It is this pressure that prevents additional molecules of the liquid from escaping from the surface of the liquid. What applies pressure to the surface of a boiling liquid? You may answer, the air molecules. 0 m ) ( π × 2 ) (Plug in numbers for ρ, g, h, and A ) F, equals, left parenthesis, 1025, start fraction, start text, k, g, end text, divided by, m, cubed, end fraction, right parenthesis, left parenthesis, 9, point, 8, start fraction, m, divided by, s, squared, end fraction, right parenthesis, left parenthesis, 63, point, 0, start text, space, m, end text, right parenthesis, left parenthesis, pi, times, open bracket, 0, point, 056, start text, space, m, end text, close bracket, squared, right parenthesis, start text, left parenthesis, P, l, u, g, space, i, n, space, n, u, m, b, e, r, s, space, f, o, r, space, end text, rho, comma, g, comma, h, comma, start text, space, a, n, d, space, end text, A, right parenthesis Since density equals mass per unit of volume ρ = m V \rho=\dfrac A) F = ( 1 0 2 5 m 3 kg ) ( 9. At this point it might not be obvious what to do, but we can simplify this expression by writing m w m_w m w m, start subscript, w, end subscript in terms of the density and volume of the water.
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